How can I let LSPDFR start a random callout? Something like

Functions.StartCallout();

But then that it starts a random callout, and that I don't have to specify one.

Functions.StartCallout takes a string parameter, this is the name specified in CalloutInfo. To achieve this, we have to get this name from all available callouts. We can do this by searching through all assemblies with a base type of Callout, retrieving the name specified in CalloutInfo, and caching it into a list of strings. When we want to trigger a random callout, we access this list and randomly choose a string with no conditions. Credit goes to Stealth22, he (as far as I know) wrote the base code for going through all callouts that I've made use of here. Gist is below with untested mock up code that should theoretically work:

 

https://gist.githubusercontent.com/RiverGrande/d27b7506d5eb1372e53f1840a8a647c8/raw/a71c93eb007f9b35e3b1e376026624507779f40e/RandomCallouts.cs

Edited March 10, 20197 yr by liverlande

5 minutes ago, liverlande said:

Functions.StartCallout takes a string parameter, this is the name specified in CalloutInfo. To achieve this, we have to get this name from all available callouts. We can do this by searching through all assemblies with a base type of Callout, retrieving the name specified in CalloutInfo, and caching it into a list of strings. When we want to trigger a random callout, we access this list and randomly choose a string with no conditions. Credit goes to Stealth22, he (as far as I know) wrote the base code for going through all callouts that I've made use of here. Gist is below with untested mock up code that should theoretically work:

 

https://gist.githubusercontent.com/RiverGrande/d27b7506d5eb1372e53f1840a8a647c8/raw/a71c93eb007f9b35e3b1e376026624507779f40e/RandomCallouts.cs

Thanks for the reply, this will help.